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35x^2-79x=-42
We move all terms to the left:
35x^2-79x-(-42)=0
We add all the numbers together, and all the variables
35x^2-79x+42=0
a = 35; b = -79; c = +42;
Δ = b2-4ac
Δ = -792-4·35·42
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-79)-19}{2*35}=\frac{60}{70} =6/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-79)+19}{2*35}=\frac{98}{70} =1+2/5 $
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